这题需要注意
题目描述
对所有员工的当前(to_date='9999-01-01')薪水按照salary进行按照1-N的排名，相同salary并列且按照emp_no升序排列 CREATE TABLE `salaries` ( `emp_no` int(11) NOT NULL, `salary` int(11) NOT NULL, `from_date` date NOT NULL, `to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`from_date`));
输入描述:
无
输出描述:
| emp_no | salary | rank |
|---|---|---|
| 10005 | 94692 | 1 |
| 10009 | 94409 | 2 |
| 10010 | 94409 | 2 |
| 10001 | 88958 | 3 |
| 10007 | 88070 | 4 |
| 10004 | 74057 | 5 |
| 10002 | 72527 | 6 |
| 10003 | 43311 | 7 |
| 10006 | 43311 | 7 |
| 10011 | 25828 | 8 |
sql:
SELECT s1.emp_no, s1.salary, COUNT(DISTINCT s2.salary) AS rankFROM salaries AS s1, salaries AS s2WHERE s1.to_date = '9999-01-01' AND s2.to_date = '9999-01-01' AND s1.salary <= s2.salaryGROUP BY s1.emp_noORDER BY s1.salary DESC, s1.emp_no ASC